Question

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The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300....​

Answer 1

Answer:

Solution: Let cost each kg of apples = Rs x

Cost of each kg of grapes = Rs y

Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x + y = 160 … (1)

2x = 160 - y

x = (160 – y)/2

Let y = 0 , 80 and 160 we get

X = (160 – ( 0 ))/2 = 80

X = (160- 80 )/2 = 40

X = (160 – 2 × 80 )/2 = 0

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4 x + 2 y = 300 … (2)

Divide by 2 we get

2 x + y = 150

Subtract 2x both side we get

Y = 150 – 2 x

Plug x = 0 , 50 , 100 we get

Y = 150 – 2×0 = 150

Y = 150 – 2 × 50 = 50

Y = 150 – 2 × (100 ) = - 50

Algebraic representation

2 x + y = 160 … (1)

4 x + 2 y = 300 … (2)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let cost each kg of apples = Rs x

Cost of each kg of grapes = Rs y

Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x + y = 160 … (1)

2x = 160 - y

x = (160 – y)/2

Let y = 0 , 80 and 160 we get

X = (160 – ( 0 ))/2 = 80

X = (160- 80 )/2 = 40

X = (160 – 2 × 80 )/2 = 0

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4 x + 2 y = 300 … (2)

Divide by 2 we get

2 x + y = 150

Subtract 2x both side we get

Y = 150 – 2 x

Plug x = 0 , 50 , 100 we get

Y = 150 – 2×0 = 150

Y = 150 – 2 × 50 = 50

Y = 150 – 2 × (100 ) = - 50

Algebraic representation

2 x + y = 160 … (1)

4 x + 2 y = 300 … (2)