Question

$\huge\underline\bold\red{Question:-}$
Three identical bulbs are connected in parallel with battery the current drawn from the battery is 6A . If one of the bulb gets fuse what will be the total current drawn from the battery?​

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Answer 1

We know that, the bulbs are identical so, they will have the same resistance and are being connected in parallel so, they will also have the same potential difference.

So, if three bulbs use 6A. So, 1 bulb uses 2A.

Thus, after when one bulb is fused the two remaining bulbs will use up 2 × 2A = 4A of current.

Therefore, the total current drawn from the battery will be 4A.