Question

$\Huge{\underline{\color{lavender}{ Question:-}}}$

$\sf \dfrac{x}{4}+\dfrac{4x}{6}=\dfrac{7x}{3}$

Solve for x

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Answer 1

$\sf \dfrac{x}{4}+\dfrac{4x}{6}=\dfrac{7x}{3} \\ \\ \frac{3x + 8x}{12} = \frac{7x}{3} \\ \\ \frac{11x}{12} = \frac{7x}{3} \\ \\ 11x \times 3 = 7x \times 12 \\ \\ 33x = 84 \\ \\ x = \frac{84}{33 } \\ \\ x = \frac{26}{11}$

#hope_it_helps_✌

Answer 2

Step-by-step explanation:

+

6

4x

=

3

7x

12

3x+8x

=

3

7x

12

11x

=

3

7x

11x×3=7x×12

33x=84

x=

33

84

x=

11

26

hopefully it will help you