Question

$\huge { \underline{ \dag {\orange{ \bold{QUESTION}}}}}$ find the volume, the total surface area , lateral surface area and the length of diagonal of a cube , each of whose edges measures 20 cm.

Answer 1

Answer:

Edge of cube = 9 m

Volume of cube =

{edge}^{3}edge3

= {9}^{3}=93

= 729=729

 so, volume of cube =729 m^3

2.Lateral surface area of cube = 4× edge^2

= 4 \times {9}^{2}=4×92

= 4 \times 81=4×81

= 324 {m}^{2}=324m2

So, Lateral Surface Area of cube = 324 m^2

3.Total surface area of cube = 6×edge^2

= 6 \times {9}^{2}=6×92

= 6 \times 81=6×81

= 486 \: m {}^{2}=486m2

So, Total Surface Area of cube = 486 m^2

Diagonal of the cube =

\sqrt{edge {}^{2} + {edge}^{2} + {edge}^{2} }edge2+edge2+edge2

= \sqrt{3 \: {edge}^{2} }=3edge2

= edge \sqrt{3}=edge3

= 9 \sqrt{3}=93

= 9 \times 1.73=9×1.73

= 15.57 \: m=15.57m

So, diagonal of cube=15.57 cm