Question

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∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e; CE?​

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Answer 1

Answer :-

Given :-

• AB = AC = 7.5 cm
• BC = 9 cm
• AD = 6 cm

To Find :-

• CE

Solution :-

Here, we have side BC and it's altitude AD. So, we will first find area of the triangle -

→ Area = ½ × BC × AD

→ Area = ½ × 6 × 9

→ Area = 3 × 9

→ Area = 27

Area of triangle = 27 cm²

Now, we have base i.e. AB and area of the triangle. So, we can find the altitude i.e. CE :-

→ Area = ½ × AB × CE

→ 27 = ½ × 7.5 × CE

→ 54 = 7.5 CE

→ CE = 54 / 7.5

→ CE = 7.2

Length of CE = 7.2 cm

Answer 2

Answer:

The area of triangle is 54cm² and height from C To AB is 7.2cm.

Step-by-step explanation:

Area of triangle= 1/2×B×H

=1/2×BC×AD

=1/2×9×6

=27cm²

Height From C to AB= 1/2×b×h

=1/2×AB×CE

Area of triangle = 1/2×7.5×CE

27cm²= 1/2×7.5×CE

27cm²×2/7.5=CE

7.2cm=CE

ANS: Hence, the area of triangle is 54cm² and height from C To AB is 7.2cm.

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