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ꜱᴛᴀᴛᴇ ᴀɴᴅ ᴅᴇʀɪᴠᴇ ᴊᴏᴜʟᴇ’ꜱ ʟᴀᴡ. ᴀɴ ᴇʟᴇᴄᴛʀɪᴄ ɪʀᴏɴ ᴄᴏɴꜱᴜᴍᴇꜱ ᴇɴᴇʀɢʏ ᴀᴛ ʀᴀᴛᴇ ᴏꜰ 420ᴡ ᴡʜᴇɴ ʜᴇᴀᴛɪɴɢ ɪꜱ ᴀᴛ ᴍᴀxɪᴍᴜᴍ ʀᴀᴛᴇ ᴀɴᴅ 180 ᴡ ᴡʜᴇɴ ʜᴇᴀᴛɪɴɢ ɪꜱ ᴀᴛ ᴍɪɴɪᴍᴜᴍ. ᴛʜᴇ ᴠᴏʟᴛᴀɢᴇ ɪꜱ 220ᴠ .ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴄᴜʀʀᴇɴᴛ ᴀɴᴅ ʀᴇꜱɪꜱᴛᴀɴᴛ ɪɴ ᴇᴀᴄʜ ᴄᴀꜱᴇ?
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Answers
Answer:
hey here is your solution
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joules law of heating expression is in above pics
Explanation:
Short Answer:
Joule's law of heating => H = I²Rt
When heating is maximum:
- I = 1.909 A
- R = 115.24 Ω
When heating is minimum:
- I = 0.818 A
- R = 268.94 Ω
Explanation:
State and derive Joule's law:
Joule's law of heating states that Heat generated is equal to the current multiplied by square of resistance and time.
Mathematically,
【H = I²Rt】
Derivation:
We know that:
W = V × Q ----- [Equation 1]
where:
- W = Work done
- V = Voltage
- Q = Charge
Also,
Q = It ----- [Equation 2]
From Ohm's law,
V = I × R ------ [Equation 3]
Put the values of V and Q from Equation 2 and Equation 3 in Equation 1.
W = V × Q
→ W = I × R × I × t
→ W = I²Rt
Here, work done = Heat produced.
So H = I²Rt
Next part of the question:
An electric iron consumes energy at rate of 420 W when heating is at maximum and 180 W when heating is at minimum. The voltage is 220 V. What is the current and resistance in each case?
Solution:
When heating is maximum:
- P = 420 W
- V = 220 V
I = P ÷ V
→ I = 420 ÷ 220
→ 『I = 1.909 A』
R = V ÷ I (Ohm's law)
→ R = 220 ÷ 1.909
→ 『R = 115.24 Ω』
When heating is minimum:
- P = 180 W
- V = 220 V
I = P ÷ V
→ I = 180 ÷ 220
→ 『I = 0.818 A』
Again by Ohm's law
R = V ÷ I
→ R = 220 ÷ 0.818
→ 『R = 268.94 Ω』