Question

$\huge\underline{\mathbb{\red{Question}}}$

The sides of a rectangular park are in the ratio 4:3. If its area is 2028 m², find the cost of fencing it at $3 per m.

${\pink{No\:Spam}}$(ಥ﹏ಥ)​

Answer 1

$\huge\underline\bold\red{Question}$

The sides of a rectangular park are in

the ratio 4:3. If its area is 2028 m².

Find the cost of fencing it at rupess 3

per m.

$\huge\underline\bold\pink{Answer}$

$\implies\sf$ Ratio of sides of rectangular park=4:3

$\implies\sf$Let length of rectangular park=4x

$\implies\sf$Let breadth of rectangular park=3x

$\implies\sf$Area of rectangular park=2028 m²

$\implies\sf$L×B=2028

$\implies\sf$4x × 3x=2028

$\implies\sf$12x²= 2028

$\implies\sf$x²=$\frac{2028}{12}$

$\implies\sf$x²= 169

$\implies\sf$$\sqrt{169}$

$\implies\sf$$\sqrt{13×13}$

$\implies\sf$13 m

$\huge{\boxed{\mathcal{\green{Length}}}}$

$\implies\sf$Length of rectangular park=4x

$\implies\sf$4(13)

$\implies\sf$52 cm

$\huge{\boxed{\mathcal{\green{Breadth}}}}$

$\implies\sf$Breath of rectangular park=3x

$\implies\sf$3(13)

$\implies\sf$39 cm

$\huge{\boxed{\mathcal{\green{Perimeter}}}}$

$\implies\sf$Perimeter of rectangular park=2(L+B)

$\implies\sf$2(52+39)

$\implies\sf$2×91

$\implies\sf$182 cm

$\huge{\boxed{\mathcal{\green{Cost}}}}$

$\implies\sf$Cost of fencing it at 1m² area= rupees 3

$\implies\sf$Cost of fencing it at 182m² area= 182×3

$\implies\sf$ rupees 546

$\huge\underline\bold\purple{ThankYou}$