A hammer having a mass of 1 kg going with a speed of 6 m/s hits a wall and comes to rest in 0.1 sec. Compute the obstacle force that makes the hammer stop.
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Answer:
Mass of the hammer=1kg
Initial velocity(u)=6ms
1
Final velocity(v)=0ms
1
Tie taken(t)=0.1sec
(i)
impluse=m(v−u)=1×(0−6)
=>−6ms
1
(ii)
a retarding force that stops a hammer
i.e.,
f=
time
impluse
=
0.1
−6
=>60N
(iii)
retarding of the hammer
i.e.,
a=
m
f
=
1
60
=60ms
−
2
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