Question

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Answer 1

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Energy in H-atom

 E=n2RH

But, given that E=9RH

⇒n2=9

n=3

As here n=3 thus there are 3 orbits. 

In general, for any energy level n, the degeneracy is given by n2

So when n= 3, the degeneracy is 9.

When n=3, the possible combinations  of (n,l.m) are (3, 2, -2), (3,2, -1), (3, 2, 0), (3, 2, 1), (3, 2, 2), (3, 1, -1), (3, 1, 0), (3, 1, 1), and (3, 0, 0)

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Answer 2

AnSwer

What do you mean by degeneracy of energy level?

if it corresponds to two or more different measurable states of a quantum system.

What do you mean by degeneracy of energy level? Find the number of degeneracy of hydrogenic orbital having energy-RH/36. RH Rydberg constant.?

Energy in H-atom

E= n 2

RH

But, given that E= 9R H

⇒n 2 =9n=3

As here n=3 thus there are 3 orbits.

In general, for any energy level n, the degeneracy is given by n2

So when n= 3, the degeneracy is 9.

When n=3, the possible combinations of (n,l.m) are (3, 2, -2), (3,2, -1), (3, 2, 0), (3, 2, 1), (3, 2, 2), (3, 1, -1), (3, 1, 0), (3, 1, 1), and (3, 0, 0)