Question

$\huge \underline \mathfrak{question : } -$


What is the moment of inertia of a wheel of

mass m and radius R having two spokes each

of mass m? (The axis of rotation is

perpendicular to the plane and passing through

centre)​

Answer 1

The moment of inertia of the ring is I$\tiny{1}$=MR²

The moment of inertia of every spoke isI$\tiny{1}$=$\dfrac{1}{3}$ mR²

since O is at the end of each spoke.

Total moment of inertia I=I$\tiny{1}$+3I$\tiny{2}$since there are three spokes.

⟹I=MR²+mR²

⟹I=(M+m)R²

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Answer 2

Answer:

Thus, required moment of inertia =Iwheel +Ispokes =(mr2)+2×[3mr2]=35mr2

Explanation:

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