If x sin³Ø+ y cos³Ø=sinØcosØ and xsinØ=ycosØ, then find the value of x²+y².
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We need to use the given condition
but we are given that -
xsin³∅+ ycos³∅ = sin ∅cos∅
we can write it as
⇒ ( xsin∅ ) sin²∅ + ( ycos∅ ) cos ²∅ = sin∅ cos ∅
⇒ xsin∅ ( sin∅ ) ²+ ( xsin∅ ) ²cos∅ = sin∅cos∅
{ ∵ xsin∅ = ycos∅ }
⇒ xsin∅ [ sin∅² + cos∅ ²] = sin∅ cos∅
⇒ xsin∅ = sin∅cos∅
or x = cos∅
Now ,
xsin∅ = ycos∅
⇒ cos∅.sin∅ = ycos∅
⇒ y = sin∅
Hence x² + y² = cos² + sin² = 1
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