Question

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Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively.​

Answer 1

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Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively.

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Algorithm

398 – 7 = 391, 436 – 11

= 425, 542 – 15 = 527

HCF of 391, 425, 527 = 17

Answer 2

Explanation:

So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.

see the pic above✌️