Question

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Answer 1

Step-by-step explanation:

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so here given simultaneous linear equations are

11/v-7/u=1 and 9/v-4/u=6

so here 11/v-7/u=1 can be written as 11×1/v-7×1/u=1

similarly 9/v-4/u=6 can be represented as

9×1/v-4×1/u=6

so then

let 1/v=m

1/u=n

thus resubstituting these values

we get

11m-7n=1 (1)

9m-4n=6 (2)

so multiplying (1) by 4 and (2) by 7

we get

44m-28n=4 (3)

63m-28n=42 (4)

subtracting (3) from (4)

we get

19m=38

ie m=2

substitute value of m in any of 4 equations

we get

n=3

resubstituting values of m and n as 1/v and 1/u

we get

1/v=m

1/u=n

ie 1/v=2

1/u=3

so v=1/2 & u=1/3

hence (v,u)=(1/2,1/3) is solution of above linear equations

Answer 2

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