Question

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Figure shows a brick of weight 2kgf and dimensions 20 cm × 10 cm × 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case.

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Answer 1

Answer:

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Area of base = 20 cm \times× 10 cm = 200 cm^2m

2

Pressure = Force/Area

P = 2 kgf 200 cm^2m

2

= 0.01 kgf cm^{-2}m

−2

Area of base = Area of top = 5 cm \times× 10 cm = 50 cm^2m

2

Pressure = Force/Area

P = 2 kgf 50 cm^2m

2

= 0.04 kgf cm^{-2}m

−2

Area of base = Area of top = 5 cm \times× 20 cm = 100 cm^2m

2

Pressure = Force/Area

P = 2 kgf 100 cm^2m

2

= 0.02 kgf cm^{-2}m

−2

Answer 2

Step-by-step explanation:

(a) Area of base = 20 cm \times 10 cm = 200 cm^2

Pressure = Force/Area

P = 2 kgf 200 cm^2 = 0.01 kgf cm^{-2}

(b) Area of base = Area of top = 5 cm \times 10 cm = 50 cm^2

Pressure = Force/Area

P = 2 kgf 50 cm^2 = 0.04 kgf cm^{-2}

(c) Area of base = Area of top = 5 cm \times 20 cm = 100 cm^2

Pressure = Force/Area

P = 2 kgf 100 cm^2 = 0.02 kgf cm^{-2}