Question

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A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim?

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Answer 1

Answer:

question - A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim?

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Answer 2

Answer:-

2 N (newton)

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To Find :-

The Minimum Force applied on the rim.

Given :-

• Diameter of the wheel :- 2 m
• Moment of force or torque = 2 N m

We know :-

• $TORQUE(T) = FORCE * PERPENDICULAR \\DISTANCE$
• $RADIUS = \frac{DIAMETER}{2}$

Concept :-

We know that a object rotate at a pivoted point , and in the this case the wheel rotate around the radius the Circle , but the diameter of the Circle is given , so by using the Formula for Radius of a circle , we can find the required value.

Given , the diameter is 2 m , so substituting the given value in the formula , we get :-

• RADIUS = 1 m

Now by this information, we can find the Force applied on the rim.

Solution :-

Given :-

Perpendicular Distance = 1 m

Moment of Force or Torque = 2 N m

Let the Force applied be F N.

Now ,

By using the formula for Torque and substituting the values in it , we get :-

TORQUE = FORCE × PERPENDICULAR DISTANCE

2 = F × 1

→ F = 2 N

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