Question

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Answer 1

Given :-

Principle amount deposited by Suhail = Rs. 8000

Annual interest rate = 18%

Time in years = 3 years

To Find :-

The interest he will get after the end of 3 years.

Solution :-

We know that,

a = Amount

p = Principle amount

r = Annual interest rate

t = Time

Using the formula,

$\underline{\boxed{\sf Amount=P \bigg( 1+\dfrac{r}{100} \bigg)^t}}$

Given that,

Principle (p) = Rs. 8000

Annual rate interest (r) = 18%

Time (t) = 3 years

Substituting their values,

⇒ a = 8000 × (1 + 18/100)³

⇒ a = 8000 × (118/100)³

⇒ a = 8000 × 1.18 × 1.18 × 1.18

⇒ a = 8000 × 1.64

⇒ a = 13120

Using the formula,

$\underline{\boxed{\sf Interest = Amount - Principal }}$

Given that,

Amount (p) = Rs. 13120

Principle (p) = Rs. 8000

Substituting their values,

⇒ 13120 - 8000

⇒ Rs. 5120

Therefore, interest he will get after the end of 3 years is Rs. 5120.

Answer 2

Step-by-step explanation:

Given :

Area of rhombus = 120 cm²

Length of diagonal = 8 cm

To find :

Length of another diagonal

According to the question,

$\sf{ : \implies Area \: of \: rhombus = \dfrac{1}{2} \times d _{1} \times d_{2} }$

$\sf : \implies{ {120 \: cm}^{2} = \dfrac{1}{2} \times 8 \: cm \times x}$

$\sf : \implies{ {120 \: cm}^{2} \times 2 = 8 \: cm \times x }$

$\sf : \implies{ {240 \: cm}^{2} = 8 \: cm \times x}$

$\sf : \implies{ \dfrac{240}{8} \: cm = x}$

${ \underline{ \boxed{ \sf \pink{ : \implies{ \bm3 \bm0 \: c m =x}}}}}$

${ \therefore{ \underline{\sf{So \:,the \: length \: of \: other \: diagonal \: is \: 3 0 \: cm}}}}$