Question

$\huge{\underline{\red{\mathfrak{♡ǫᴜᴇsᴛɪᴏɴ♡}}}}$⠀⠀⠀⠀At constant temperature 200 cm³ of $\sf{N_2}$ at 720 mm and 400 cm³ of $\sf{O_2}$ at 750 mm pressure are put...​

Answer 1

Correct option is

D

444 mm

The number of moles of nitrogen n=

RT

PV

=

RT

720×200

The number of moles of oxygen n

′

=

RT

PV

=

RT

750×400

The final pressure P=

V

nRT

=

1000

RT

720×200

+

RT

750×400

RT=

1000

144000+300000

=444 mm.

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Answer 2

The number of moles of nitrogen n=RTPV=RT720×200

The number of moles of oxygen n′=RTPV=RT750×400

The final pressure P=VnRT=1000RT720×200+RT750×400RT=1000144000+300000=444 mm.

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