Question

$\Huge{\underline{\sf Physics\: Question:-}}$

Mass and volume of a block are measured as 22.42g and 4.7 cm$^3$.Find the maximum possible error in density.

1)0.6%
2)2.2%
3)2.8%
4)3.2%​

Answer 1

Answer:

2.8 is answer

please mark brainlist

Answer 2

Given:-

Mass = 22.42 g  

Volume = 4.7 cm³

Suppose the maximum possible error of mass and volume are 0.01 g and 0.1 cm³.  

Density=  $\frac{Mass of block}{Volumeofblock}$

We need to calculate the maximum possible error in density  

Using formula of density:-

Δρ/ρ × 100 = Δm/m × 100 + ΔV/V × 100

Substitute the values

Δρ/ρ × 100 = 0.01/22.42 × 100 + 0.7/4.7 × 100

Δρ/ρ × 100 = 2.2%