If 2,5,8,11are in A.P .
Find:-
☆37th term of an A.P.
☆Sum of first 19terms.
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Step-by-step explanation:
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First term=2=a
Common difference d=5-2=3
And anth=a+(n-1)d
Now a 37 =a+(37-1)d
=>a 37=2+(36)5
=>a 37=2+180=182
Now s 19=n/2[2a+(n-1)]d
=>s 19=19/2[2×2+(19-1)5]
=>s 19=19/2[4+90]
=>s 19=19/2×94
=>s 19=19×47
=>s 19=893
☆37th term of an A.P is 182.
☆Sum of first 19terms is 893.
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