Question

${\huge{\underline{\small{\mathbb{\pink{DERIVATION \ OF \ PARALLELOGRAM \ LAW}}}}}}$​

Answer 1

Answer:

The Parallelogram law states that the sum of the squares of the length of the four sides of a parallelogram is equal to the sum of the squares of the length of the two diagonals. In Euclidean geometry, it is necessary that the parallelogram should have equal opposite sides. 2(AB)2 + 2 (BC)2 = (AC)2 + (BD)2.

Explanation:

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Answer 2

Explanation:

Let P and Q be two vectors acting simultaneously at a point and represented both in magnitude and direction by two adjacent sides OA and OD of a parallelogram OABD as shown in figure.

Let θ be the angle between P and Q and R be the resultant vector. Then, according to parallelogram law of vector addition, diagonal OB represents the resultant of P and Q.

So, we have

R = P + Q

Now, expand A to C and draw BC perpendicular to OC.

From triangle OCB,

In triangle ABC,

Also,

Magnitude of resultant:

Substituting value of AC and BC in (i), we get

which is the magnitude of resultant.

Direction of resultant: Let ø be the angle made by resultant R with P. Then,

From triangle OBC,