if and then show that :-
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Given :-
x = acos³θ and y = bsin³θ
To Find :-
Prove that ( x/a )^2/3 + ( y/b )^2/3 = 1
Used Concepts :-
- Sin² x + Cos² x = 1
- ( x^m )^n = x^m × n
Solution :-
Let us start with the Given i.e
x = a cos³θ
=> x/a = cos³θ ----- ( i )
y = b sin³θ
=> y/b = sin³θ ----- ( ii )
=> Now we will prove which we have to do :)
=> ( x/a )^2/3 + ( y/b )^2/3 = 1
Let LHS i.e ( x/a )^2/3 + ( y/b )^2/3
=> ( Cos³θ )^2/3 + ( Sin³θ )^2/3
{ Using ( i ) and ( ii ) }
=> { ( Cosθ )³ }^2/3 + { ( Sinθ )³ }^2/3
=> ( Cosθ ) ² + ( Sinθ ) ²
{ Because , ( x^m )^n = x^m × n }
=> Cos²θ + Sin²θ
{ Because Cos² x + Sin² x = 1 }
=> 1
LHS = RHS
Henceforth , Proved :)
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