Question

${\huge{\underline{\underline{\bf{Question:-}}}}}$
$if \: ( {x}^{2} + \frac{ {1}}{x {}^{2} } ) = 102 \: then \: (x - \frac{1}{x} ) =$
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Answer 1

Step-by-step explanation:

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Answer 2

${\huge{\underline{\underline{\bf{Question:-}}}}}$

$if \: ( {x}^{2} + \frac{ {1}}{x {}^{2} } ) = 102 \: then \: (x - \frac{1}{x} ) =$

$\large{\underbrace{\sf{\red{Required \:answer:}}}}$

➔$( {x}^{2} + \frac{ {1}}{x {}^{2} } )$ = 102

➔$( {x}^{2} + \frac{ {1}}{x {}^{2} } )$-2=100

➔${x-1/x}^{2}$= ${10}^{2}$

➔${x-1/x}$=10

$\huge{\underline{\sf{\red{Thanks}}}}$