Question

$\huge{\underline{\underline{\mathfrak\green{Question\::}}}}$

Area of a rectangular field is 300 sq.m .There is a path outside the field width 4 m. Length of the field is 20 m. Find area of the path.

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Answer 1

AnswEr :

⋆ Refrence of Image is in the Attachment :

• Area of Rectangluar Field = 300 m²
• Length of the Field = 20 m
• Breadth of the Field = ?

• Area of Rectangluar Field will be :

⇒ Area = Length × Breadth

⇒ 300 m² = 20 m × Breadth

• Dividing both Side by 20 m

⇒ Breadth = 15 m

_______________________________

⋆ Width for any side = (2 × 4) = 8 m

• Outer Length ( L ) = (20 + 8) = 28 m
• Outer Breadth ( B ) = (15 + 8) = 23 m
• Inner Length ( l ) = 20 m
• Inner Breadth ( b ) = 15 m

• Area of the Path around the Field :

↠ Area of Path = Outer Area – Inner Area

↠ Area of Path = (L × B) – (l × b)

↠ Area of Path = [(28 × 23) – (20 × 15)] m²

↠ Area of Path = [644 – 300] m²

↠ Area of Path = 344 m²

∴ Area of the Path around field is 344 m².

Answer 2

Answer:

$\huge{\boxed{\mathfrak\purple{Answer:344\:{m}^{2}}}}$

Given,

• Area of the field = 300 sq.m
• Length of the field = 20 m
• Width of path = 4 m
• Area of path = ?

Solution:-

Length of the field = 20 m

Area of the field = 300 sq.m

$\therefore\tt Breadth =\frac{300}{20}\:m$

$\Rightarrow\tt Breadth = 15\:m$

__________________________

$\tt Length\:of\:field\:including\:path =(20+ 2 \times 4)\:m$

$\Rightarrow\tt Length\:of\:field\:including\:path = 28\:m$

$\tt Breadth\:of \:filed\: including\:path =(15 + 2\times 4)\:m$

$\Rightarrow\tt Breadth\:of \:field\:including\:path = 23 \:m$

$\tt Area\:of \:field\:including\:path =(28 \times 23)\:{m}^{2}$

$\Rightarrow\tt Area\:of\:field\:including\:path = 644\:{m}^{2}$

$\tt Area\:of\:path = (644 - 300)\:{m}^{2} \\ \\ \Rightarrow\tt Area\:of \:path = 344\:{m}^{2}$

$\therefore\tt {\underline{Area\:of\:path =344\:{m}^{2}}}$