Question

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Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. Find their present ages.​

Answer 1

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son = x+5

Present age of father = 7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10 = 3(x+10)

7x−3x = 20

4x = 20

x = 5

So, the present age of son = x+5=5+5 = 10years

and the present age of father = 7x+5 = 35+5 = 40years

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Answer 2

Step-by-step explanation:

❒ Given :-

Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. Find their present ages.

❒ To Find :-

Find their present ages.

❒ Solution :-

Let Five years ago the age of son be x years and age of father be 7x years :

⇒ Present age of son = x+5

⇒ Present age of father = 7x+5

⇒ 5 years later their age will (x+10) and (7x+10) =

∴7x+10 = 3(x+10)

⇒ 7x−3x = 20

⇒ 4x = 20

⇒ x = 5

• So, the Present age of son = x+5 = 5+5 = 10 Years
• The Present age of father = 7x+5 = 35+5 = 40 Years

Hence , Your Answer Is 10 Years And 40 Years

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