Question

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An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as must current as all three appliances and what is the current through it?






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Answer 1

Answer:

Resistance

R=R1+R2+R3

50+500+ 100

=650 OHM

CURRENT

V= Q×T

SUBSTITUE THEM IN THIS FORMULA

Answer 2

❥ᴛᴏ ғɪɴᴅ

• Resistance of an electric iron.
• The flow of electric current through the electric iron.
• The three resistors are connected in parallel as shown in the below figure.

❥Given parameters:

• Resistance of electric lamp (R1) = 100 Ω
• Resistance of toaster (R2) = 50 Ω
• Resistance of water filter (R3) = 500 Ω
• Potential difference of the source (V) = 220 V.

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1. Total resistance (R) can be calculated as shown below.

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/100 + 1/50 + 1/500

1/R = ( 5 + 10 + 1 )/500

1/R = 16/500

500/16 = R

Total Resistance (R) = 500/16 Ω

R = 31.25 Ω

2. According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.

V ∝ I or V = IR

➯R is constant called resistance.

R = V/I

500/16 = 220/I

I = 220 × (16/500)

I = 7.04 A

• Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.

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❥ʜᴏᴘᴇ ʜᴇʟᴘs ᴜ ᴅᴇᴀʀ♡