Question

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What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistances 4 Ω, 8 Ω, 12 Ω, 24 Ω?






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I need help please help please​

Answer 1

Answer:

Highest will be by series = 4 + 12 + 8 + 24 = 48ohms

Lowest will be by parallel = 1/R = 1/4 + 1/8 + 1/24 + 1/12 = 12/24 = 1/2

So , R = 2

Answer 2

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