Question

$\Huge\underline{\underline{\sf \red{Question}:}}$

Calculate Molecular Weight of $\sf{Na_2CO_3}$ ​

Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}\mid}}}$

$Na_{2} CO_{3}$

Molecular weight of Na is 23

for two Na it will be 46

Molecular weight of C is 12

Molecular weight of O is 16

For 3 oxygen it will be 48

$\therefore For \: \: Na_{2}CO_{3} , \\ \\ Molecular \: \: weight \: \: will \: \: be \: \: \\ 46+12+48 = 106 u$

Answer 2

=}Molar mass of Na2CO3 = 105.98844 g/mol

Molecular weight calculation:

22.98977*2 + 12.0107 + 15.9994*3

Mass Percent

Sodium( Na) 22.989770 2 43.382%

Carbon( C )12.0107 1 11.332%

Sodium( Na) 22.989770 2 43.382%