Question

${i}^{55} + {i}^{60} + {i}^{65} + {i}^{70} =$
Answer this question with proper steps

Answer 1

break the powersandu will get the ans.

Answer 2

We know that i^2 = -1.

Given i^55 + i^60 + i^65 + i^70

= > (i^54 * i) + [(i^2)^30] + i^64 * i + (i^2)^35

= > [(i^2)^27 * i] + [(-1)^30] + [(i^2)^32 * i] + (-1)^35

= > [(-1)^27 * i] + (1) + [(-1)^32 * i] + (-1)

= > -i + 1 + i - 1

= > 0.

Hope this helps!