Question

$i)...( {998)}^{2} \: \:( ii) \: 78 \times 82$
using identities....(a-b) (a+b) +(b-c) (b+c) +(c-a) (c+a) =0

please slove in detail

Answer 1

Hey user

Here is your answer :-

( 998 )^2 = ( 1000 - 2 )^2

= ( 1000 )^2 - 2 ( 1000 )( 2 ) + ( 2 )^2

= 1000000 - 4000 + 4

= 996000 + 4

= 996004 .

78 × 82

= ( 80 - 2 )( 80 + 2 )

= ( 80 )^2 - ( 2 )^2

= 6400 - 4

= 6396

Thank you .

Answer 2

Aryan PVT..LTD........