Math, asked by nmbawo, 9 months ago

I=\frac{prnx}{100y} A=P(1+in) A=P(1+\frac{rnx100y}

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Answered by megha200515
0

Answer:

I=\frac{prnx}{100y} A=P(1+in) A=P(1+\frac{rnx100y}

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