Math, asked by shadowsabers03, 1 year ago

$$I'm sure only less than 1\% of you can solve this problem. \\ \\ \\

$$If you find this, then you'll be the very brilliant and genius in the whole world. \\ \\ And also I'm giving you 50 points each. \\ \\ So I'm challenging.

$$Found this question and reason yesterday. Not from any other sources. The question's on my own. \\ \\ \\ Okay.

$$Consider the equality given below.

\frac{3x+1}{3x+2} = \frac{3x+2}{3x+1}

$$By cross multiplication, we get,

(3x+1)(3x+1) = (3x+2)(3x+2) \\ \\ \Rightarrow (3x+1)^2=(3x+2)^2

$$By taking their square roots, we get,

3x+1=3x+2

$$By subtracting$\ 3x\ $from both sides, we get,

1=2

$$How is this possible?! \\ \\ Find where I'd mistaken. \\ \\ Also find the real value of$\ x. \\ \\

$$If you find it, then you'll be the real$\ \bold{`brainliest}$'!!! \\ \\ \\ SO I'M CHALLENGING!!!

\#adithyasajeevan


mkrishnan: hai what is wrong in x and nx problem that you reported
shadowsabers03: That's x and 2x.

Answers

Answered by Anonymous
43

Answer:

x = -1/2

Not using latex to save time .

Hope it helps !

Step-by-step explanation:

First of all it is given that :

( 3 x + 1 ) / ( 3 x + 2 ) = ( 3 x + 2 ) / ( 3 x + 1 )

Let ( 3 x + 1 ) / ( 3 x + 2 ) be t

So :

t = 1 / t

⇒ t² = 1

⇒ t = ± 1

( 3 x + 1 ) / ( 3 x + 2 ) = ± 1

⇒ 3 x + 1 = either ( 3 x + 2 )

Or ⇒ 3 x + 1 = - ( 3 x + 2 )

Considering : 3 x + 1 = - 3 x - 2

⇒ 6 x = -2 - 1

⇒ x = -3/6

⇒ x = -1/2

Hence x = -1/2

Now see the first one :

3 x + 1 = 3 x + 2

First of all this is not possible because 1 ≠ 2

Hence this should not be considered .

Now :

( 3 x + 1 )² = ( 3 x + 2 )²

Next step is WRONG :

Whenever x² = a²

either x = a OR x = - a

x may not be a !

Eg :

( 5 )² = ( - 5 )²

We cannot say 5 = - 5 .

When x² = a² |x| = |a| !

And this was a problem that even bad students can solve . It is not so complex .

This is the basis of mathematics problems .

It cannot be said difficult at all .

This is the main Point ^^"


Anonymous: thank u but who can verify this ? O_o
yahootak: a mod
yahootak: obviously
yahootak: xD
Anonymous: not all mods can verify ... I am shocked with this incident O_o .. anyways JAI HIND __/\__
yahootak: see you have gained so many vizard ranks now, therefore you r special user
yahootak: now
shadowsabers03: If I didn't ask this question, would you gain these achievements?!
shadowsabers03: JishnuMukherjee, can I ask you a question?
Anonymous: ask any question . I don't want to achieve anything in a virtual World .
Answered by Anonymous
9

Answer:

It is the correct answer.

Step-by-step explanation:

Kindly verify my answer!

Hope this attachment helps you.

Attachments:
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