Question

$if \: {1}^{2} + {2}^{2} + {3}^{2} \\ then \\ {4}^{2} + {5}^{2} +{ {?}^{2} } = {21}^{2} \\ what\: will\: be \:in \: the \: question\: mark$
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Answer 1

Answer:

answer- ?= 12²

Step-by-step explanation:

let no. be x

1. add (4+5)²
2. subtract the product of above with 21²
3. you will get answer.

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