Question

$If\ \ 2x - \frac{1}{3} = \sqrt{2x - \frac{1}{3}}, \\ \\ what\ are\ the\ possible\ values\ of\ x? \\ \\ \\ (Hint:\ There\ are\ two\ values\ for\ x.)$

Answer 1

Answer:

Step-by-step explanation:

take     y = 2x - 1/3

now             y =√y

                   y^2 = y    then    y =0 or y =1

case 1    y=0

          2x= 1/3

            x=1/6

case 2   y =1

       2x -1/3 = 1

     2x = 1+ 1/3

      2x = 4/3

        x =2/3

Answer 2

Step-by-step explanation:

hope it will help you..