Question

$if \: {5}^{2 \: x \: + \: 1} \: \div \: 25 \: = \: 125 \: find \: the \: value \: of \: x$
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Answer 1

Answer:

5^(2x + 1) ÷ 25 = 125

5^(2x + 1) ÷ 5^2 = 5^3

5^(2x + 1) = 5^2 × 5^3

5^(2x + 1) = 5^5

2x + 1 = 5

2x = 4

X = 2

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