Question

$if \: a = (1. - 2. - 1) b = (4.0. - 3) c = (1.2. - 1) \: and \: d(2 . - 4. - 5) find distance b\a and ab and cd.$
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Answer 1

Answer:

Explanation:

Given :

• A = (1 , - 2 , - 1) , B = (4 , 0 , - 3) , C = (1, 2, - 1) and D = (2 , - 4 , - 5).

To Find :

• The distance between AB and CD.

Formula to be used :

• Distance between two points = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

Solution :

★A = (1 , - 2 , - 1) and B = (4 , 0 , - 3).

AB = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

→ √(4 - 1)^2 + (0 - (-2)^2 + (-3 - (-1)^2

→ √(3)^2 + (2)^2 + (-2)^2

→ √9 + 4 + 4

→ √17 units

★C = (1, 2, - 1) and D(2 , - 4 , - 5).

CD = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

→ √(2 - 1)^2 + (-4 - 1)^2 + (-5 - 1)^2

→ √(1)^2 + (-5)^2 + (-6)^2

→ √1 + 25 + 36

→ √62 units

Hence,The distance between AB and CD is √17 and √62 respectively.