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It is given that, a² + b² = 7ab
or, a² + b² + 2ab = 2ab + 7ab
or, (a + b)² = 9ab
taking log both sides,
log(a + b)² = log(9ab)
or, 2log(a + b) = log(9ab) [ using formula (2), ]
or, 2log(a + b) = log9 + loga + logb [ using formula (1), ]
or, 2log(a + b) = log3² + loga + logb
or, 2log(a + b) - 2log3 = loga + logb
or, 2[ log(a + b) - log3 ] = loga + logb
or, 2log{ (a + b)/3 } = loga + logb
hence, it is clear
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