Question

$if a = 2 + \sqrt{3} \: \: find \: the \: value \: of \: \: a \: cube \: + \frac{1}{a \: cube \: \: \: \: .}$
​

Answer 1

Answer:

Trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).

Answer 2

Answer:

answer :

a = 2 + V3

1

a

1

2 + 3

On rationalizing the denominator we get,

1

a

1

2 + 3

2 - 3

2 - V3

Using the identity :

(x + y)(x – y) = x² – y?

1

a

2 - V3

(2)² – (v3) 2

1 2 - 13

a 4 - 3

1 a = 2 - V3

1

a a

Putting the values,

1 a = (2 + V3) - (2 - V3)

a

1 a = 2 + v3 – 2 + v3

a

a V3+ v3 a

1 a a - 2/3

hope it helps

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