Question

$If \: \: a+b=7 \: \: and \: \: ab = 4, find \: \: the \: \: value \: \:of \: \: a2+b2$

Answer fast please ....​

Answer 1

Answer:

The answer is 41

Step-by-step explanation:

Given $a+b=7$ and $ab=4$

Using identity

                  $\boxed{(a+b)^2=a^2+b^2+2ab}$

We have        

                    $7^2=a^2+b^2+2(4)$  Substitute the given values

                    $\Rightarrow 49=a^2+b^2+8\\\Rightarrow a^2+b^2=49-8=41$