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applying cos on both sides
cos (A+B+C)=cos(180)
cot A cotB cotC+cotB cotA-1/cotA+cotB+cotC-cotA cotB cotC =1/2
cot(A+B+C)=cot A cotB+cotC +cotB cotA-1/cotA+cotB+cotC-cotA cotB cotC
cotA+cotB+cotC- cotA cotB cotC=0
cotA+cotB+cotC=cotA cotB cotC
cotA+cotB+cotC/cotA cot B cot C=1
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