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Step-by-step explanation:
Let a^x = b^y = c^z = abc = k
a^x = k => a = k^ (1/x). Similarly, b = k^(1/y) and c = k^(1/z)
Now abc = k
=> k^(1/x) k^(1/y)k^(1/z) = k
=> k^{(1/x + 1/y + 1/ z)} = k^1
Since the bases are same we can equate the indices.
Hence we get 1/x + 1/y + 1/z = 1.
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