Question

$if \alpha \: and \: \beta are \: roots \: of \: a \: quadratic \: equation \: 3 {x}^{2} - 5x + 4 = 0 \: find \: the \: value \: of \: \frac{1}{ \alpha } + \frac{1}{ \beta } \: - 2 \alpha \beta$
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Answer 1

Answer:

-17/12

Step-by-step explanation:

α+β = 5/3 , αβ = 4/3

$\frac{1}{\alpha } +\frac{1}{\beta } - 2\alpha\beta$

= $\frac{\alpha+\beta}{\alpha\beta } - 2\alpha\beta$

= $\frac{5/3}{4/3} - 2 * 4/3$

= 5/4 - 8/3

= -17/12