Question

$If cos x= \sqrt{3 } \div 2 then \: find the value of\ \textless \ br /\ \textgreater \ 3 sinx -4sin^3x$
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Answer 1

Answer:

cos x=

$\sqrt{3 \div 2}$

x=30

sin 30=1/2

4 sin^3x = 4 sin^3(30)

= 4×(1/2)^3

=4/2×2×2

=1/2

Your answer is 1/2

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