Question

$if \\ \: \cot\alpha = \tan( \beta + \gamma ) \\ so \: proved \: that \\ \: \: \sin( \alpha + \beta + \gamma ) = 1$
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Answer 1

Answer:

COTα=TAN(β+γ)

TAN(90-α)=TAN(β+γ)

90-α=β+γ

α+β+γ=90   (1)

SIN(α+β+γ)

SIN(90)    (FROM 1)

=1 as sin90=1 (trigonometric ratios)

Step-by-step explanation: