Question

$if \: \cot \: theta = 1 \div 2 \: \: \: then \: find \: \sec theta - \tan \: theta$
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Hey frnd...

Ur ans is...

$= \sqrt{5} - 2$

Step-by-step explanation:

Given

$\cot(theta) = \frac{1}{2} = \frac{base}{prependicular} \\ thus \: base = 1 \\ \: prendicular = 2 \: and \: hypo = \sqrt{5} \\ \sec(theta) = \frac{hypo}{base} \\ = \sqrt{5} .............(1) \\ \tan(theta) = \frac{prep}{base} \\ = 2.............(2) \\ now \\ = \sec(theta) - \tan(theta) \\ = \sqrt{5 } - 2$

Hope this helps u.