Math, asked by Tehreemf309, 5 hours ago


if \frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} }  =  \frac{a}{2}  +  \frac{b \sqrt{5} }{2}   \\ find \: a \: and \: b \:
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Answers

Answered by negivardhan993
1

Explanation:

\mathsf{\frac{7+3\sqrt5}{7-3\sqrt5}}

\mathsf{=\frac{(7+3\sqrt5)(7+3\sqrt5)}{(7-3\sqrt5)(7+3\sqrt5)}}

\mathsf{=\frac{7^2+2(7)(3\sqrt5)+(3\sqrt5)^2}{7^2-(3\sqrt5)^2}} [∵ \mathsf{(a+b)^2=a^2+2ab+b^2,\:(a+b)(a-b)=a^2 - b^2}]

\mathsf{=\frac{49+42\sqrt5+45}{49-45}}

\mathsf{=\frac{94+42\sqrt5}{4}}

\mathsf{=\frac{94}{4}+\frac{42\sqrt5}{4}}

\mathsf{=\frac{47}{2}+\frac{21\sqrt5}{2}}

\mathsf{\frac{7+3\sqrt5}{7-3\sqrt5}=\frac{a}{2}+\frac{b\sqrt5}{2}}

\mathsf{==>\frac{a}{2}+\frac{b\sqrt5}{2}=\frac{47}{2}+\frac{21\sqrt5}{2}}

\mathsf{a=47,\:b=21}

Answer: a = 47, b = 21

I hope this helps. :D

Answered by cugarshen
2

Answer:

a=94. b =42. [100% correct ] , Mark BRAINLIST

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Please Mark as BRAINLIST answer, If I am right.

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