Question

$if \: \frac{ {x}^{2} }{ {x}^{2} + 3x + 1 } = a \ \\ \\ then \: find \: the \: value \: of \\ \frac{ {x}^{2} }{ {x}^{4} + 3 {x}^{2} + 1}$
solve it, with step

Answer 1

$\frac{ {x}^{2} }{ {x}^{2} + 3x + 1 } = a \\ \frac{ {x}^{2} + 3x + 1}{ {x}^{2} } = \frac{1}{a } \\ 1 + \frac{3}{x} + \frac{1}{ {x}^{2} } = \frac{1}{a} ......(1) \\ \\ \\ to \: find \\ \frac{ {x}^{2} }{ {x}^{4} + 3 {x}^{2} + 1} = m(let) \\ \\ or \\ {x}^{2} + 3 + \frac{1}{ {x}^{2} } = \frac{1}{m}$
solve these 2

Answer 2

Answer:

Hope it's helpful to you