Math, asked by Adrita25, 1 month ago


if \:  \: m +  \frac{1}{m}  = 99 \:  \: then \:  \frac{100m}{3^{2} + 103m + 3 } =
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Answers

Answered by nitukaur270
0

ANSWER : For inline formulas, enclose the formula in $...$. For displayed formulas, use $$...$$.

These render differently. For example, type

$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$

to show ∑

n

i=0

i2=

(n2+n)(2n+1)

6

(which is inline mode) or type

$$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$

to show

n

i=0 i2=

(n2+n)(2n+1)

6

hope it helps

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his second example::

Let I=7

n

+7

m

, then we observe that 7

1

,7

2

,7

3

and 7

4

ends in 7,9,3 and 1 respectively.

Thus, 7

1

ends in 7, 9, 3 or 1 according as i is of the form 4k + 1, 4k + 2, 4k - 1 and 4k respectively.

If S is the sample space, then n(S)=(100)

2

7

m

+7

n

is divisible by 5, if

(i) m is of the form 4k + 1 and n is of the form 4k - 1 or

(ii) m is of the form 4k + 2 and n is of the form 4k or

(iii) m is of the form 4k - 1 and n is of the form 4k + 1 or

(iv) m is of the form 4k and n is of the form 4k + 2 or

So, number of favourable ordered pairs (m,n)=4×25×25

∴ Required probability =

(100)

2

4×25×25

=

4/1

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