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ANSWER
(a)
The resonance frequency is given by
ω=
LC
1
=
5×80×10
−6
1
=50rad/s
The resonant frquency is 50 rad/s.
(b)
At resonance, ωL=1/ωC
⇒Z=R=40Ω
The peak voltage, V
o
=
2
V
I
o
=
2
V/Z
I
o
=8.13A
(c)
Potential drop across inductor,
V
L(rms)
=I×ω
R
L
I=I
0
/
2
=
2
V/
2
Z=23/40 A
⇒V
rms
=1437.5V
Potential drop across capacitor,
(V
c
)
rms
=I×
w
r
C
1
=1437.5V
Potential drop across resistor,
(V
R
)
rms
=I×R=230V
Potential drop across the LC combination
V
LC
= I(X
L
-X
C
)
at resonance X
L
=X
C
⇒V
LC
=0 V
Step-by-step explanation:
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Step-by-step explanation:
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