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sivaprasath:
nice one
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Sec²@ - tan²@ =1
Sec@ + tan@ =p
So, sec@ - tan@ =1/p
Adding both we get,
2sec@ = p+1/p
or, sec@ = ½(p+1/p)
or, cos@ =2 p/(1+p²)
Sin@ = root ( 1- (2p/(1+p²))²)
____= 1/(1+p²)root(1+2p²+p⁴ - 4p⁴)
____= 1/(1+p²)root((p²-1)²)
Sin@ =(p²-1)/(1+p²)
Hope this is ur required answer.
Sec@ + tan@ =p
So, sec@ - tan@ =1/p
Adding both we get,
2sec@ = p+1/p
or, sec@ = ½(p+1/p)
or, cos@ =2 p/(1+p²)
Sin@ = root ( 1- (2p/(1+p²))²)
____= 1/(1+p²)root(1+2p²+p⁴ - 4p⁴)
____= 1/(1+p²)root((p²-1)²)
Sin@ =(p²-1)/(1+p²)
Hope this is ur required answer.
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