Question

$if \: sec \: = \: \frac{13}{12} \: find \: all \: trignomtric \: ratio$

Answer 1

HOLA

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$sec \: = \: \frac{h}{b} = \: \frac{13}{12} \\ \\ ac {}^{2} = \: ab {}^{2} \: + \: bc {}^{2} \\ \\ bc {}^{2} = \: ac {}^{2} - \: ab {}^{2} \\ \\ bc {}^{2} = \: (13) {}^{2} - \: (12) {}^{2} \\ \\ bc {}^{2} = \: 169 \: - \: 144 \: = \: 25 \\ \\ \sqrt{25} = \: 5 \\ \\ sin \: = \: \frac{5}{13} \: \: \: cos \: = \: \frac{12}{13} \\ \\ tan \: = \: \frac{5}{12} \: \: cot \: = \: \frac{12}{5} \\ \\ sec \: = \: \frac{13}{12} \: \: cosec \: = \: \frac{13}{5}$

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HOPE U UNDERSTAND ❤❤❤

Answer 2

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Step-by-step explanation:

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